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valentinak56 [21]
3 years ago
12

Please give me the correct answer.Only answer if you're very good at math.Please don't put a link to a website.Please use the Py

thagorean Theorem formula which is a^2 + b^2 =c^2.​

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

The answer would be C

Step-by-step explanation:

To find the answer square the 12 yds and subtract that from 30 yds squared. That will leave you with 27.49, and you would just round that decimal up to 27.5 for youir answer.

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A pharmacist has 40% and 60iodine solutions on hand. How many liters of each iodine solutions will be required to produce 4 lite
Schach [20]

A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?

.

Let x = liters of 40% iodine

then

4-x = liters of 80% iodine

Using algebra:

.40x + .80(4-x) = .50(4)

.40x + 3.20-.80x = 2

3.20-.40x = 2

x = 4 liters (40% iodine)

80% iodine:

4-x = 4-4 = 0 liters needed (80% iodine)

4 0
3 years ago
Which ordered pair is the solution to the system of equations?
d1i1m1o1n [39]
\begin{cases}-3x+4y=-20\\y=x-4\end{cases}\\\\\\-3x+4(x-4)=-20\\\\-3x+4x-16=-20\\\\x-16=-20\quad|+16\\\\x-16+16=-20+16\\\\\boxed{x=-4}\\\\\\y=x-4\\\\y=-4-4\\\\\boxed{y=-8}

Answer C.
4 0
2 years ago
Use the lim f(x)-f(a)/x-a to find the derivative.
Tresset [83]
Hello,

f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)

lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11

Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11



at point(1,-7)

4 0
3 years ago
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
3 years ago
Represent the following expressions as a power of the number a (a≠0)((a^2)^−2)^5÷(a^4a)^3
nikklg [1K]

Answer:

a⁻³⁵

Step-by-step explanation:

((a²)⁻²)⁵ ÷ (a⁴a)³

((a²)⁻²)⁵ ÷ (a⁴a¹)³

= (a⁻⁴)⁵ ÷ (a⁵)³

= a⁻²⁰ ÷ a¹⁵

= a⁻²⁰⁻¹⁵

= a⁻³⁵

Exponent rules:

Multiplying two numbers with same base: add exponents

Dividing two numbers with same base: subtract exponents

Number with exponent raised to another exponent: multiply the exponents together

4 0
3 years ago
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