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nikklg [1K]
3 years ago
15

On Monday the temperature is 0F on Tuesday it is seven degrees warmer what is the temperature?

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

7F

Step-by-step explanation:

Add 7 to 0

0+7 = 7F

Iteru [2.4K]3 years ago
5 0

Answer:

obviously 7F

Step-by-step explanation:

Just add 7 to the zero and its 7F

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Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle
erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

P=2L+W+\frac{1}{2}\pi D

we have

L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}

substitute

P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)

P=20)+7+11=38\ ft

therefore

Helen will need 38 feet of fencing

Part 2)  What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

L=10\ ft\\W=7\ ft

substitute

P=2(10)+7

P=20+7=27\ ft

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

C=\frac{1}{2}\pi D

we have

D=7\ ft\\\pi =\frac{22}{7}

substitute

C=\frac{1}{2}(\frac{22}{7})(7)

C=11\ ft

therefore

The approximate distance around half of the circle is 11 feet

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3 years ago
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kenny6666 [7]
Y=1
x=50 y=5 50 is 10 times more than 5, the proportion is x is 10 times more, so you always divided 10 from x
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An oil rig has a height of 74.98 m visible above water and extends 518.16 m below the surface to the sea floor. What is the tota
pashok25 [27]

Answer:

  1. So you know that the height that is visible above x=0 is 74.98 m
  2. From x=0 below it has a total height of 518.16m to the sea floor

That tells us that we have two parts account for

  1. 74.98+518.16m = 593.14 m
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