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natulia [17]
3 years ago
11

plzzzzz help me with this question . write the base and coefficient in the following terms=a.3y b. -2× c.X d. 4abc e.4(a+b f.5×​

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

a gas in a rigid container has a pressure of 632 torrs and a temperature of 45 celsius. The pressure has increased to 842 torrs. What is the new temperature of the gas

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What is the 100th term of the arithmetic sequence below?<br> 4, 11, 18, 25
galina1969 [7]

Answer:

a₁₀₀ = 697

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 4 and d = a₂ - a₁ = 11 - 4 = 7 , then

a₁₀₀ = 4 + (99 × 7) = 4 + 693 = 697

8 0
3 years ago
Evacuate 3 1.5 + 2 2.3
zaharov [31]

Answer:

53.8

Step-by-step explanation:

31.5 + 22.3

53.8

Hope it helps

3 0
3 years ago
Read 2 more answers
The pipe has a length 29cm, internal diameter 6.5cm and thickness 0.5cm. What is the Volume
Reptile [31]

Answer:

Length of pipe = 21 cm

Internal diameter = 4 cm

Internal radius = \frac{4}{2} = 2 cm24=2cm

Thickness = 0.5 cm

Outer radius = 2+0.5=2.5 cm

Volume of pipe =\pi R^2 h - \pi r^2 hπR2h−πr2h

Volume of pipe =\frac{22}{7} (2.5)^2 (21)-\frac{22}{7}(2)^2(21)=148.5 cm^3

=\frac{22}{7} (2.5)^2 (21)-\frac{22}{7}(2)^2(21)=148.5 cm^3722(2.5)2(21)−722(2)2(21)=148.5cm3

Hence The volume is 148.5 cubic cm.

#more

The thickness of a metal pipe is 1.5cm. The inner diameter is 21cm. What is the volume of metal required for a pipe of length 7cm

5 0
2 years ago
H(y)=9/5 • 2y at y=-2
Deffense [45]

Answer:

H( - 2) = - 7  \frac{1}{5}

Step-by-step explanation:

We want to evaluate the equation

H(y) =  \frac{9}{5}  \times 2y

at y=-2

We just have to substitute to obtain;

H( - 2) =  \frac{9}{5}  \times 2 \times  - 2

We now multiply to get:

H( - 2) =  \frac{9}{5}   \times  - 4

This is the same as:

H( - 2) =  \frac{9}{5}  \times \frac{ - 4}{1}

We multiply the numerators separately and denominators separately to get:

H( - 2) =  \frac{9 \times  - 4}{5 \times 1}

H( - 2) =  \frac{ - 36}{5}

This implies that

H( - 2) = - 7  \frac{1}{5}

6 0
3 years ago
The cost of 1 purse and 1 watch is £27.
EastWind [94]
1 purse and 1 watch is 27€
2 purse and 1 watch is 41€

So we can see the watch is constant means 1 watch is every time but purse is increase by 1 in the next expression

So 41-27 = 14€ is one purse
because the watch is every time one, so the next value increase is by purse

1purse and 1watch = 27
We know,
1 purse is 14€
So 27-14=13€ is one watch

We can check by
1 purse is 14 so two purse is 14*2=28
28+13=41
Which is same as they said in second expression

Hope it help you!¡

4 0
2 years ago
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