Answer:
4,5,27
Problem:
Boris chose three different numbers.
The sum of the three numbers is 36.
One of the numbers is a perfect cube.
The other two numbers are factors of 20.
Step-by-step explanation:
Let's pretend those numbers are:
.
We are given the sum is 36: 
.
One of our numbers is a perfect cube. 
where 
is an integer.
The other two numbers are factors of 20. 
and 
where 
.
From here I would just try to find numbers that satisfy the conditions using trial and error.
So I have found a triple that works:
The numbers in ascending order is:
Answer:
Opción b, P(2) = 0
Step-by-step explanation:
Tenemos la expresión:
P(y) = y^2 - 7*y + 10
Para encontrar el valor P(2), simplemente debemos remplazar todas las "y" en la expresión de arriba por el valor 2, asi obtenemos:
P(2) = 2^2 - 7*2 + 10 = 4 - 14 + 10 = (4 - 14) + 10 = -10 + 10 = 0
P(2) = 0
La opción correcta es b.
Answer:
Suppose that x is some number so 6 times a number is 6*x. 20 more than that number is 20 + x. If you put it together the inequality would be 6x > 20 + x. Subtracting x from both sides would result in 5x > 20. Dividing by 5 gives you x > 4 which is the final answer. So the possible values of that number is anything greater than 4.
Answer:
B. x more than 40
Step-by-step explanation:
If you would like to win the tug of war game, you would have to apply a more greater force to win. If Team B needed to win, over 40 lbs. of force would do.
