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3 years ago

Can someone please explain to me how to do this

Mathematics

1 answer:

muminat3 years ago

8 0

Step-by-step explanation:

u should:

7t = t + 48 » 7t - t = 48 » 6t = 48 » t = 8

and another one is:

2u + t + 13 = 10t + u - 44» 2u + 8 + 13 = 80 + u - 44»

» 2u + 21 = u + 36 » 2u - u = 36 - 21 » u = 15

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If the x is the number, how would you represent 9 more than the number

Roman55 [17]

Answer:

x = x+9

Step-by-step explanation:

well that is the only way you can do it as we do not know about what x is. also, if you meant by x + (x*9), you can represent that as x*10

8 0

3 years ago

200 3. A technician charges $25 per hour plus $50 for a house call to repair home computers. Make a table and a graph to show th

Tju [1.3M]

Recall that for a home visit, the technician charges $50 regardless on the time spent in the repair.

So, to find out the rate, we should calculate the part that depends on the spent time, and the add 50. So for example, we know that the technician spents 1 hour. So, we multiply 1 times 25 and then add 50. So, 25*1 + 50 = 75, which is the rate for a 1-hour repair.

So, in general, if we know that the number of hours is x, we multiply x times 25 and then add 50. Then a table would like this:

x 25*x 25*x +50

1 25 75

2 50 100

3 75 125

4 100 150

Note that as the time increases by one hour, the fare increases by 25. This is an example of a direct variation, since as the independent variable increases (t

6 0

1 year ago

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0

3 years ago

Which expression represents the word phrase the product of 3 and 6 more than a number? 3(x+6) 3(6−x) 3x + 6 I don't know.

tatuchka [14]

Answer:

3(6+x)

Step-by-step explanation:

PLESAE GIVE BRAINLIEST

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2 years ago