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2 years ago

What do factors 16 and 24 have in common? plz help

Mathematics

2 answers:

marta [7]2 years ago

5 0

Answer:

both factors contain 8

Step-by-step explanation:

16 = 4 x 4 or 2 x 2 x 2 x 2

24 = 4 x 6 or 2 x 2 x 2 x 3

2 x 2 x 2 = 8

both have 8

yanalaym [24]2 years ago

4 0

8 is the largest common factor. other common factors are 1, 2, and 4

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3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

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3 years ago

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sergiy2304 [10]

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2 years ago

What is the difference in hours and minutes between these times 10:35 2:40

MA_775_DIABLO [31]

Answer:

10:35

11:35

12:35

1:35

2:35

=Thats 4 hours

and then 40-35=5

So 4hours 5 minutes

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2 years ago

Read 2 more answers

The supplement of an angle is 3 times the complement of an angle.

-Dominant- [34]

Let’s says that x is the measure of the angle. X and it’s supplement are equal to 180. X and it’s complement are equal to 90. The supplement is s and the complement is c. S is times c which is the same as 3c.

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C+x = 90
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The complement of. 45 degree angle is 45 degrees.

The angle is 45 degrees.

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3 years ago

Urgenttttt please I need it fast

dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

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= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

= 5^-2 x^2y^-4 / 625 x^4y^-2

= 5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

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2 years ago