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marishachu [46]
2 years ago
12

Hi,

Mathematics
1 answer:
lyudmila [28]2 years ago
3 0

Here I have answered your question. Hope this helps. pls give brainliest if possible. tks. Have a nice day!!

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A set of bivariate data was used to create a least squares regression line. Which of the following is minimized by the line
77julia77 [94]

Answer:

B) The sum of the squared residuals

Step-by-step explanation:

Least Square Regression Line is drawn through a bivariate data(Data in two variables) plotted on a graph to explain the relation between the explanatory variable(x) and the response variable(y).

Not all the points will lie on the Least Square Regression Line in all cases. Some points will be above line and some points will be below the line. The vertical distance between the points and the line is known as residual. Since, some points are above the line and some are below, the sum of residuals is always zero for a Least Square Regression Line.

Since, we want to minimize the overall error(residual) so that our line is as close to the points as possible, considering the sum of residuals wont be helpful as it will always be zero. So we square the residuals first and them sum them. This always gives a positive value. The Least Square Regression Line minimizes this sum of residuals and the result is a line of Best Fit for the bivariate data.

Therefore, option B gives the correct answer.

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2 years ago
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What do you do to check whether a number is rational or irrational
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Irrational numbers cant be fraction and can be written as a decimal. An irrational number has Endless repeating numbers
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What is the radius and diameter of the following circle?
Cerrena [4.2K]

Answer:

Radius=9

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Step-by-step explanation:

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Given: M(-4,-1), B(-5,-3) find the midpoint
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\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
%  (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -5}}-4}{2}\quad ,\quad \cfrac{-3-1}{2} \right)
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Its c I've done this before
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