. Simplify an expression for the area of the rectangle shown above

Please answer this correctly without making mistakes

Alex73 [517]

Answer:

i believe that would be 5t-8

Step-by-step explanation:

hopefully this helps :)

have a nice day !!

**please let me know if this was wrong**

8 0

3 years ago

2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.

Ad libitum [116K]

The value of x is 77 cm which will make the triangles similar by SSS similarity theorem

Given length of the three sides of one triangle are 35 , 20 and 20

and length of the three sides of another triangle are x, 44,44

We need to find the values of x by using SSS Similarity theorem

We know that triangles are are similar by side - side - side similarity creation and hence the sides are in the same ratio

As both the triangles are isosceles triangles

Therefore ,

x/35 = 44/20=44/20 (Using ratio)

Solving the equation we get

x=44*35/20

x= 77

Hence the value of x is 77cm

Learn more about similarity of triangles here brainly.com/question/14285697

#SPJ10

8 0

1 year ago

What is the first step needed to solve 3 over 4 multiplied by x minus 3 equals negative 18?

kodGreya [7K]

Minus 3 from the 3 and the 18

7 0

3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

9. A group of 14 friends went to a basketball game and paid a total of $70 for their admission tickets. They received a discount

lukranit [14]

the answer is $7

Step-by-step explanation:

70 divided by 14 is 5.

cost would be $5 per person before discount of $2

$5 plus $2 equal $7

p= $7

4 0

2 years ago