Answer:
Need a picture of the problem.
Step-by-step explanation:
Answer:
We have, 2x+y=3 .......(1)
xy=1....(2)
In equation (2), we get
y=
x
1
..........(3)
y put in the equation (1)
2x+
x
1
=3
2x
2
+1=3x
2x
2
−3x+1=0
2x
2
−3x−1x+1=0
2x(x−1)−1(x−1)=0
x=1, x=
2
1
We take the value of x=1
x value put in equation (1)
2(1)+y=3
y=3−2
y=1
x=1
x and y value put (x+y)
x−y
=(1+1)
(1−1)
=2
0
=1
Hence, this is the answer
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Answer:
that is simplified as much as possible
Answer:
![\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Yes%20%5C%5C%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bf%28x%29%7C-2%20%E2%89%A4%20f%28x%29%20%E2%89%A4%204%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%204%5D%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C0%20%E2%89%A4%20x%20%E2%89%A4%207%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B0%2C%207%5D)
Step-by-step explanation:
Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.
* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.
** This is kind of like a sine wave.
I am joyous to assist you anytime.
It is equal to. I think its because the zeros don't count