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KatRina [158]
3 years ago
9

Anyone who answers this correctly I WILL GIVE U A SUPER THANKS

Mathematics
1 answer:
Inga [223]3 years ago
3 0

Answer:

25

Step-by-step explanation:

4x+8+72=180

4x+80=180

180-80=100

100/4=25

x=25

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The length of a rectangle is 5 less than 3 times the width. What is the length?
Tanzania [10]

Answer:

Let the width of the Rectangle be x inches

Then, length is (3x-5) inches

Perimeter of the Rectangle= 46 inches (given)

According to the above problem,

Equation :---- Perimeter=2(length+breadth)

<u>2{(3x-5)+x}=46</u>

2(4x-5)=46

(4x-5)=46/2=23

4x=(23+5)=28

x=28/4

<u>x=7</u>

So, length of the Rectangle is {(3×7)-5}=16 inches

and width is= 7 inches

5 0
3 years ago
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Y - 11 = 3(x-2) write an equation in slope intercept form
Alekssandra [29.7K]
The answer is: Y = 3x+5
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4 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
X⁴-12x²+36 equals what
Harrizon [31]
Hello there!

From that amount of information, you can't get a numerical value for the answer.

Hope This Helps You!
Good Luck :)
6 0
3 years ago
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HELP ME PLZ ASAP!!!!!!!!!!!
kondor19780726 [428]
(8q)/4 ..................
3 0
4 years ago
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