Answer:
13, 17, 19
Step-by-step explanation:
Go through (12-20) and find the multipliers for each number.
13 = 13 x 1
14 = 7 x 2 , 14 x1 = no
15 = 5 x 3, 15 x 1 = no
17 = 17 x 1
18 = 6 x 3, 9 x 2, 18 x 1 = no
19 = 19 x 1
I believe it would be tan
No real solution
you must take the square root of a -3 which gives you an imaginary number
Answer:
<u>Given:</u>
- DC ║ AB
- CM = MB as M is midpoint of BC
i) <u>Since DN and BC are transversals, we have:</u>
- ∠DCM ≅ ∠NBM and
- ∠CDM ≅ ∠BNM as alternate interior angles
<u>As two angles and one side is congruent, the triangles are also congruent:</u>
- ΔDCM ≅ ΔNBM (according to AAC postulate)
So their areas are same.
ii)
<u>The quadrilateral has area of:</u>
- A(ADCB) = A(ADMB) + A(DCM)
<u>And the triangle has area of:</u>
- A(ADN) = A(ADMB) + A(NBM)
Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.
