To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
1964.16 is hundredth
1964.2 is tenth
1964 is one
1960 is ten
2000 is hundred
Answer:
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Step-by-step explanation:
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Answer:
j
Step-by-step explanation:
Substitute the given values into x² + x + 1 and check if result is prime
x = - 4
(- 4)² - 4 + 1 = 16 - 4 + 1 = 13 ← prime
(- 2)² - 2 + 1 = 4 - 2 + 1 = 3 ← prime
(- 3)² - 3 + 1 = 9 - 3 + 1 = 7 ← prime
4² + 4 + 1 = 16 + 4 + 1 = 21 ← not prime
x = 4 serves as a counterexample to disprove this conclusion
Step-by-step explanation:
A=P(1+i)^n
=5,000(1+5%/4)^10×4
=$8,218.10