The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
Answer:
4/25
Step-by-step explanation:
6 1/4=25/4
The reciprocal of 25/4 is 4/25.
B. x^2 + 5x - 4 = 0
Anyway that you try to factor it will not work
~~hope this helps~~
Answer:
its -160
Step-by-step explanation:
:)
Answer: their is 50 percent that it will land on heads
Step-by-step explanation: it will have a completely random chance no matter how many times you flip a coin on tails it will always have a fifty percent chance even if you flipped the coin 1000000 and it landed on tails all those times it would still have the fifty fifty probability of landing on heads hope this has helped and good question
