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Afina-wow [57]
3 years ago
7

Can someone help me with exercise 121?

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0
It would be
(X^4+2X^2) -119(X^2-2X) then you would simplify
X^4+2X^2-119X^2-2X
So it would be
X^4+117X^2-2X=0
So basically X is undefined
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MEC makes a big family tent in the shape of a symmetrical triangular prism. The floor of the tent is 5 m long and 2.5 m wide. Th
SVEN [57.7K]

Answer:

15,236 sq in

Step-by-step explanation:

First, you have to split the net into three rectangles and two triangles

step 1

triangular base area

1/2 bh = 1/2 (44 in)(64 in)

= 1/2 (2,816 sq in)

= 1,408 sq in.

2 x 1,408 sq in = 2,816 sq in.

step 2

end rectangle area

lw = (68 in)(69 in)

= 4,692 sq in

2 x 4,692 sq in = 9,384 sq in

Now find the area of the middle rectangle

lw - (69 in) (44 in) = 3,039 sq in.

then add all the areas together

2,816 + 9,384 + 3,036 = 15,236 sq in

Hope this helps :)

3 0
3 years ago
Mindy conducted a survey of the phones in 4 stores and wrote The Following observations:
balu736 [363]
The first one is 75% i think I dont know if thats the answer though hold on and I'll get you the others

5 0
3 years ago
The circumference of a circle is 60 cm. What is the diameter
Mariana [72]
<h2>d ≈ 19.1 cm</h2>

<em>Using the formulas</em>

<em>C = 2πr</em>

<em>d = 2r</em>

<em>Solving for 'd' (diameter)</em>

<em>d = C</em>

<em>π = 60</em>

<em>π ≈ 19.09859cm</em>

<em />

7 0
2 years ago
Pleasee help I'm really struggling ​
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The cost of Tulip and Roses are 1500LL and 2500LL respectively

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The area of a rectangle is 479.4 square feet. The width of the rectangle is 17 feet.
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The answer is 28.2 because 479.4 ft. ÷ 17 ft. = 28.2 ft.

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