Explain how you can use compatible numbers to estimate the whole-number quotient of 925÷29.
1 answer:
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The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5
we have
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2
using the graph
for x=5 the approximate value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15
the answer is
the approximate value of y is 1.15
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5
we have
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2
using the graph
for x=5 the approximate value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15
the answer is
the approximate value of y is 1.15
Answer:
For more than 500 minutes
Step-by-step explanation:
Let x be the number of minutes.
<u>First company</u> charges:
$0.029 per minute, then $0.029x for x minutes
and a $2 monthly fee.
In total, $(0.029x+2)
<u>Second company</u> charges:
$0.033 per minute, then $0.033x for x minutes
with no monthly fee.
If the charges for the first company are cheaper, then
Multiply this inequality by 1,000:
Answer:
C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is higher than 14, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one side test the p value would be:
Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to reject the null hypothesis
The best option would be:
C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.