Answer: >>> for count in range(10, 14):
print(count)
Explanation:
just took the test on edg
<span>B. users vote on the relevance of the source, which affects whether it will appear in future searches. </span>
Answer:
nest an else clause within an elif clause
Explanation:
in python Programming, we cannot nest an else clause within an elif clause. elif is actually else if condition. we cannot nest another else with in elif clause.
Answer:
The next step to consider is updating the system's network settings
Explanation:
The next step after testing and verifying that the network patch cable and network interface card are working is to update the network settings to recent configurations.
Updating the system's network include settings of network adapter, LAN / Wi-Fi and TCP/IP.
Looking into your network settings is one of steps of effectively troubleshooting a system's network.
Few settings you could update are
1. LAN settings
2. TCP/IP network protocol properties
3. Network adapter settings
4. Internet connection
Effectively, updating the network settings is the next step. Few things to take note of when updating the network settings are
1. Create Standard Configurations for Device Classifications
2. Maintain the Current and Previous Network Configurations
3. Keep Track of Changes
4. Lastly, Document Network Changes
Answer:
The solution code is written in Python
- import random
-
- mystery_int_1 = 3
- mystery_int_2 = 4
- mystery_int_3 = 5
- print(str(mystery_int_1) + " " + str(mystery_int_2) + " " + str(mystery_int_3))
-
- while(mystery_int_1 > 0 or mystery_int_2 > 0 or mystery_int_3 > 0 ):
- mystery_int_1 = random.randint(-5, 5)
- mystery_int_2 = random.randint(-5, 5)
- mystery_int_3 = random.randint(-5, 5)
- print(str(mystery_int_1) + " " + str(mystery_int_2) + " " + str(mystery_int_3))
Explanation:
Firstly import random module (Line 1).
Next, create three variables to hold the three mystery numbers (Line 3-5). Display the first set of three mystery numbers in one line (Line 6).
While any one of the three mysteries number still bigger than zero, the while loop will keep going (Line 8). In the loop, three new mystery numbers will be generated using the randint method (Line 9-11). We presume the random value is in range -5 to 5. Print the new set of mystery number on the same line (Line 12).
