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lesya692 [45]
3 years ago
14

(-4a^3bc^2)(a^3b^2c)(3ab^4c^5)​

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:( -22•3a7b7c8)

Step-by-step explanation:

STEP1

Equation at the end of step 1

 ((0-(((4•(a3))•b)•(c2)))•(((a3)•(b2))•c))•(3ab4•c5)

STEP 2

Equation at the end of step2

 ((0 -  ((22a3 • b) • c2)) • a3b2c) • 3ab4c5

STEP 3

Multiplying exponential expressions :

3.1    a6 multiplied by a1 = a(6 + 1) = a7

Multiplying exponential expressions :

3.2    b3 multiplied by b4 = b(3 + 4) = b7

Multiplying exponential expressions :

3.3    c3 multiplied by c5 = c(3 + 5) = c8

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Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.
expeople1 [14]
Rewriting the two equations:

[Supply] p = q^2+20
[Demand] p=-4q^2+10q+18600

Equilibrium price is when 
Supply = Demand
q^2+20 = -4q^2+10q+18600
q^2+4q^2+20-10q-18600 = 0
5q^2-10q-18580=0 ⇒ Simplifying the equation by dividing each term by 5

q^2-2q-3716=0

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula. 

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation. 
q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}, and q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}


We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97
q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62
4 0
3 years ago
Step by step 579÷3 plz i need help
ololo11 [35]
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Step-by-step explanation:

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The correct choice is option C) 4/8.

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2 years ago
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