m∠B = 33° is the answer.
<u>Step-by-step explanation:</u>
If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.
In any triangle, sum of the measure of the angles add up to 180°.
∠A+ ∠B+ ∠C = 180°
∠A ≅ ∠M
∠B ≅ ∠O
∠C ≅ ∠P
So we can add as,
∠A + ∠B+ ∠P = 180°
45° + ∠B + 102° = 180°
∠B + 147° = 180°
∠B = 180° - 147° = 33°
The second answer that uses = is not correct, because the pentagons are similar not congruent.
The third answer is not correct, because that sign means estimated, not similar.
I've never seen the fourth sign, so by process of elimination I believe the answer is the first one.
<span>ABCDE~QRSTU</span>
Answer:
x=2 AB=hypotenus(h) angle ACB is 90
BC=p angle CAB is 30 also angle of refrence
Step-by-step explanation:
sin[30]=p/h
(1/2)=x/4
2x=4
x=2
