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3 years ago

How do we Round with any numbers, (on a number line) ?

Mathematics

2 answers:

Firdavs [7]3 years ago

7 0

Answer:

round it to the nearest 10th?

Step-by-step explanation:

that's what I do at least.

Stells [14]3 years ago

6 0

Answer: Round up or down.

Step-by-step explanation: When you round up, look at the number to the right of the number you wanna round. If it’s less than 5, you round down, if it’s more than 5, you round up. On a number line, for ex. Let’s say you wanna round 550 to hundreds, 600 or 500, 600 would be the answer because 550 is more closer to 600 by default.

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Can someone help meeee?

nadya68 [22]

Answer:

F ( 2 , -2)

Step-by-step explanation:

8 0

3 years ago

Divide. HELP ASAP PLEASE!!

VashaNatasha [74]

Answer:

The answer to your question is below

Step-by-step explanation:

a) $\frac{s^{2}- 3s - 28 }{s - 7}$

Factor the numerator is a polynomial of the form x² + bx + c

s² - 3s - 28 = (s - 7)( s + 4)

Substitute

$\frac{(s - 7)(s + 4)}{(s - 7)}$

Simplify like terms

Result s + 4

b) $\frac{c^{2} + 5c - 24}{c + 8}$

Factor the numerator is a polynomial of the form x² + bx + c

c² + 5c - 24 = (c + 8)(c - 3)

Substitute

$\frac{(c + 8)(c - 3)}{c + 8}$

Simplify like terms c - 3

Result c - 3

3 0

3 years ago

Answer Question number 5 Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$