Answer:
We start with the equation:
(x^2 - 1)/(x + 1) = 2
We want to rewrite this in standard form.
We can multiply both sides by (x + 1) to get:
((x^2 - 1)/(x + 1))*(x + 1) = 2*(x + 1)
x^2 - 1 = 2*(x + 1) = 2*x + 2
Now we can move all the terms to one side to get:
x^2 - 1 - 2 - 2*x = 0
x^2 - 2*x - 3 = 0
And this is a standard quadratic equation, that we can solve by using the Bhaskara's formula, this will give us the solutions:
![x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4*1*(-3)} }{2*1} = \frac{2 \pm 4}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-%28-2%29%20%5Cpm%20%5Csqrt%7B%28-2%29%5E2%20-%204%2A1%2A%28-3%29%7D%20%7D%7B2%2A1%7D%20%20%3D%20%5Cfrac%7B2%20%5Cpm%204%7D%7B2%7D)
Then the two solutions are:
x = (2 + 4)/2 = 3
x = (2 - 4)/2 = -1
The factor of intensity increase for each whole number increase in the Richter scale is 10. This is because the Richter scale is a logarithmic scale that has a base of 10. As an example, a Richter scale of 1 increased to 2 will have an intensity increase of
10^2 / 10^1 = 10
Answer:
The answer is "3006 ns"
Step-by-step explanation:
The time is taken by
taking time
first taking time
Calculating the Rest taking 3 ns to process
For 1000:
![= 9+ 3\times 999\\\\= 9+2997\\\\=3006\ ns](https://tex.z-dn.net/?f=%3D%209%2B%203%5Ctimes%20999%5C%5C%5C%5C%3D%209%2B2997%5C%5C%5C%5C%3D3006%5C%20ns)
Answer:
There is an 85% probability that the sprinkler head will be activated.
Step-by-step explanation:
We have these following probabilities:
50% of the first sprinkler being triggered
90% of the first sprinkler being reliable
50% of the second sprinkler being triggered
80% of the second sprinkler being reliable.
What is the probability that the sprinkler head will be activated?
![P = P_{1} + P_{2}](https://tex.z-dn.net/?f=P%20%3D%20P_%7B1%7D%20%2B%20P_%7B2%7D)
is the probability of the first sprinkler being triggered and activated. So:
![P_{1} = 0.5*0.9 = 0.45](https://tex.z-dn.net/?f=P_%7B1%7D%20%3D%200.5%2A0.9%20%3D%200.45)
is the probability of the second sprinkler being triggered and activated. So:
![P_{2} = 0.5*0.8 = 0.40](https://tex.z-dn.net/?f=P_%7B2%7D%20%3D%200.5%2A0.8%20%3D%200.40)
![P = P_{1} + P_{2} = 0.40 + 0.45 = 0.85](https://tex.z-dn.net/?f=P%20%3D%20P_%7B1%7D%20%2B%20P_%7B2%7D%20%3D%200.40%20%2B%200.45%20%3D%200.85)
There is an 85% probability that the sprinkler head will be activated.
The correct answer is: [F]: "rational" .
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It is not an "integer" because it is a "decimal value".
It is not "irrational" because the decimal value terminates and does not repeat.
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