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Elena-2011 [213]
3 years ago
12

What would be the new value of a after running the program

Mathematics
1 answer:
atroni [7]3 years ago
4 0

Answer:

The answer is 15

Step-by-step explanation:

3 \times 5 = 15

You might be interested in
Chris has 115$ to spend at a shopping mall . If he decides to spend $42 on clothing and $37 on food how much money will he have
Katena32 [7]

Answer:

$36 left

Step-by-step explanation:

42+37=79

115-79=36

7 0
3 years ago
Is the relationship shown by the data linear? How can you tell if it is or is not? If so, model the data with an equation.
Marat540 [252]

Answer:

linear and y = 2x + 19

Step-by-step explanation:

the x- values increment by 2 and the values of y increment by 4

This indicates a linear relationship exists in the form

y = mx + c ( m is the slope and c the y-intercept )

m = \frac{rise}{run} = \frac{4}{2} = 2

y = 2x + c ← is the partial equation

to find c use any ordered pair from the table

using (- 5, 9 ), then

9 = - 10 + c ⇒ c = 9 + 10 = 19

y = 2x + 19 ← linear equation

As a check

x = - 7 : y = - 14 + 19 = 5 ← correct value of y

x = - 5 : y = - 10 + 19 = 9 ← correct value of y

x = - 3 : y = - 6 + 19 = 13 ← correct value of y

x = - 1 : y = - 2 + 19 = 17 ← correct value of y


4 0
3 years ago
Factor the equation in the picture ​
algol [13]

Answer:

A

Step-by-step explanation:

-5 y^ - I5 y=0

-5 y (y +3) =0

5 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
Please help with #49
Anuta_ua [19.1K]

Answer:

A

Step-by-step explanation:

The inverses of functions are basically the Xs and Ys swapped. For example, the inverse of (2,-3) is (-3,2).

Thus, the inverse of (-2,4), (3,2), and (-6,10) will be (4,-2), (2,3), and (10,-6).

the answer is A.

8 0
3 years ago
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