The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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1. y = c - x
2. y = ( t - 3x ) / 2
3. y = ( 4p ) / 3
4. y = ( 2 - 4s ) / 3s
Answer:
8275382+9162672(7263382) 615-41+8162(71818)
Answer:
743.13
Step-by-step explanation:
area of the rectangle is 33x11 which is 363 and there are two equal half circles so we can just pretend they are connected so the radius is 11 A=pi times 
which is 380.13 then add both of them and you get 743.13
Answer:
5.4.
Step-by-step explanation:
If we divide 2 by 5 we get 0.4
So 5 and 2/5 = 5.4
