Answer:
![perimeter=90](https://tex.z-dn.net/?f=perimeter%3D90)
Step-by-step explanation:
We know that the length is four times the width, so:
![l=4w](https://tex.z-dn.net/?f=l%3D4w)
We also know the area, which is 324 m². The formula for area:
![A=l*w](https://tex.z-dn.net/?f=A%3Dl%2Aw)
Insert the known values:
![324=(4w)*w](https://tex.z-dn.net/?f=324%3D%284w%29%2Aw)
Solve for w. Simplify by removing parentheses:
![324=4w*w\\324=4w^2](https://tex.z-dn.net/?f=324%3D4w%2Aw%5C%5C324%3D4w%5E2)
Divide 4 from both sides to isolate the variable:
![\frac{324}{4}=\frac{4w^2}{4} \\\\81=w^2](https://tex.z-dn.net/?f=%5Cfrac%7B324%7D%7B4%7D%3D%5Cfrac%7B4w%5E2%7D%7B4%7D%20%20%5C%5C%5C%5C81%3Dw%5E2)
Find the square root of both sides:
![\sqrt{81} =\sqrt{w^2} \\\\w=9](https://tex.z-dn.net/?f=%5Csqrt%7B81%7D%20%3D%5Csqrt%7Bw%5E2%7D%20%5C%5C%5C%5Cw%3D9)
The width is 9 m.
We know the width. Now find the length by using the area formula and inserting known values:
![324=l*9](https://tex.z-dn.net/?f=324%3Dl%2A9)
Solve for l. Divide both sides by 9:
![\frac{324}{9}=\frac{l*9}{9}\\\\ l=36](https://tex.z-dn.net/?f=%5Cfrac%7B324%7D%7B9%7D%3D%5Cfrac%7Bl%2A9%7D%7B9%7D%5C%5C%5C%5C%20%20l%3D36)
The length of the rectangle is 36. (You can check: 4 times 9 is 36)
Now find the perimeter:
![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
Insert values:
![P=2(36)+2(9)\\\\P=72+18\\\\P=90](https://tex.z-dn.net/?f=P%3D2%2836%29%2B2%289%29%5C%5C%5C%5CP%3D72%2B18%5C%5C%5C%5CP%3D90)
The perimeter is 90 m.
Answer:
C. Moved all terms from left to right that doesn't contain y
Y=-6 +1/3x-3
Simplify
Y=1/3x-9
Step-by-step explanation:
Divide the diameter by 2 to get the radius and then plug into cone volume pi*r^2*h/3 which is a bit under 160 so the answer is A
Answer:
(2,1)
Step-by-step explanation:
X=2 and y=1