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VikaD [51]
3 years ago
14

A transformation describes a change in location, orientation, or size of a figure. Translations, reflections, and rotations belo

ng to the subcategory of transportations called rigid transformations. Why do you think these are called rigid transformations?
pls help i will give brainly!
Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer: These are called rigid transformations because the structure and shape of the shape remains the same.

Step-by-step explanation: The word rigid and rigidity is often used to describe something that is tough or the strength of something. The transformations might be called a rigid transformation because the rigidity of the shape remains the same because the size is the exact same, it is the exact same shape it is just moved.

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Find the value of x, y, and z in the parallelogram below.
telo118 [61]

The values of x, y, and z of the parallelogram are -19°, -115° and 27°

<h3>What is a parallelogram?</h3>

A parallelogram is a two-dimensional geometrical shape whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length. The Sum of adjacent angles of a parallelogram is equal to 180 degrees.

for a parallelogram opposite angles are equal

-4x -1 = 75

-4x = 76

x = 76/-4

x = -19°

sum of adjacent angles are supplementary

(-y-10) + 75 = 180

-y + 65 = 180

-y = 180 - 65

-y = 115

y = -115°

Also

4z - 3 + 75 = 180

4z + 72 = 180

4z = 180 - 72

4z = 108

z = 108/4

z = 27°

In conclusion, the values of x = -19, y = -115, z = 27

Learn more about Parallelogram: brainly.com/question/20526916

#SPJ1

8 0
1 year ago
HI i neeed helppppppppppppppppp
elena-14-01-66 [18.8K]

Answer:

5

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
1 year ago
What is the connection between rate and slope
Paraphin [41]

Answer:

Step-by-step explanation:

In math, slope is the ratio of the vertical and horizontal changes between two points on a surface or a line. The vertical change between two points is called the rise, and the horizontal change is called the run. The slope equals the rise divided by the run: . This simple equation is called the slope formula.

6 0
3 years ago
2 sin x + V3 = 0<br> i need help answering this
Lady_Fox [76]

Answer:

2 sin x + √3 = 0

2sinx=-√3

sinx=-√3/2

x=sin-¹(-√3/2)(sin-¹ means inverse of sin)

x=-60

7 0
3 years ago
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