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3 years ago

What is the slope of the line through [-1,2] and [2,-3]

Mathematics

1 answer:

Gennadij [26K]3 years ago

8 0

Answer:

-3/5

Step-by-step explanation:

to figure that out you have to do y^2 - y^1/ x^2 - x^1

2-(-1)/ -3 - 2

= 3/-5

=-3/5

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Find the distance between the points (1,3) and (5,0).

Irina18 [472]

distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2

I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

5 0

3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

3/4 − 2/5 in a fraction

Dennis_Churaev [7]

Answer:

7/10

Step-by-step explanation:

6 0

3 years ago

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scoray [572]

Answer:

Step-by-step explanation:

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8 0

3 years ago

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Maria drives 130 miles in 2 hours. If she keeps driving at the same speed without stopping, what is the total time it will take

zlopas [31]

It would take her 10 hours.

Explanation: 650 divided by 130 is 5 and 2 hours multiplied by 5 hours is 10 hours. Sorry if I got it wrong, but hoped I helped.

3 0

2 years ago

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