A rectangle has an area of 18 square units. What can be said of its height and width? Check all that apply.

Mathematics

1 answer:

Eddi Din [679]2 years ago

8 0

Answer: A, B, and C

Step-by-step explanation:

Area = Length x Width

A. With these dimensions, the area would be 18 sq units

1 * 18 = 18

B. With these dimensions, the area would be 18 sq units

3 * 6 = 18

C. With these dimensions, the area would be 18 sq units

6 * 3 = 18

D. With these dimensions, the area would be 80 sq units

8 * 10 = 80

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PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!

jonny [76]

Answer:

Here we will use the relationships:

$a^n*a^m = a^{n + m}$

$(a^n)^m = a^{n*m}$

$\frac{a^n}{a^m} = a^{n - m}$

And a number:

$a^n$

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) $5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}$

This is between zero and 1,

B) $\frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}$

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C) $(\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5$

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) $\frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}$

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

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2 years ago

20 points!! Solve this system of lineal equations.separate the x- and y- values with a comma

Zielflug [23.3K]

Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1

Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.