Answer:
Yes.
Step-by-step explanation:
U will get 9,699,232
(2x10)+(4x1)+(3x1/10)+(5x1/100)+(7x1/1000)
1/10,1/100,1000 are fractions
I think you add both of them together and you get 145
C is the correct answer for m
<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
