Question

Multiply both equations by a constant

Answer 1

Answer:

(- $\frac{1}{3}$, $\frac{3}{4}$ )

Step-by-step explanation:

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

Multiplying (1) by 12 and (2) by 8 and adding will eliminate the y- term

108x + 96y = 36 → (3)

48x - 96y = - 88 → (4)

Add (3) and (4) term by term to eliminate y

156x = - 52 ( divide both sides by 156 )

x = $\frac{-52}{156}$ = - $\frac{1}{3}$

Substitute this value into either of the 2 equations and solve for y

Substituting into (1)

9(- $\frac{1}{3}$ ) + 8y = 3

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = $\frac{6}{8}$ = $\frac{3}{4}$

solution is (- $\frac{1}{3}$, $\frac{3}{4}$ )