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Gennadij [26K]
2 years ago
9

Solve for x………………………

Mathematics
1 answer:
k0ka [10]2 years ago
4 0

4×11+1=45

A+B+C=180 60+75+C=180 180_130=c c=45

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The equation for the line is
Y=1x+0 or just Y=1x
4 0
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If a box in the group has a length of 30 inches what is its volume
USPshnik [31]
V=a^3
v=30^3
v=27000in^3
7 0
3 years ago
If the system below were written as a matrix equation, by which matrix could you multiply both sides to obtain a solution?
ludmilkaskok [199]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices:

A. 
<span>[8 -6] </span>
<span>[-5 4] </span>
<span>B. </span>
<span>[4 -3] </span>
<span>[-2.5 2] </span>
<span>C. </span>
<span>[-4 5] </span>
<span>[6 -8] </span>
<span>D. </span>
<span>[-2 2.5] </span>
<span>[3 -4]
</span>
B because it is the inverse of 
<span>(4 6) </span>
<span>(5 8) </span>

<span>Check </span>
<span>(4.0 -3)(4 6) = (1 0) </span>
<span>(-2.5 2)(5 8) = (0 1)</span>
3 0
3 years ago
The cost, C. of producing coolers, x, is modeled by the equation C = 0.005x2 - 0.3x + 17. How many coolers are
melamori03 [73]

Answer:

66 coolers

Step-by-step explanation:

C = 0.005x² - 0.3x + 17

When C = $19

19 = 0.005x² - 0.3x + 17

19 - 17 = 0.005x² - 0.3x

2 = 0.005x² - 0.3x

0.005x² - 0.3x - 2 = 0

x = -b ± √b² - 4ac / 2a

= -(-0.3) ± √-0.3² - 4*0.005*-2 / 2*0.005

= 0.3 ± √ 0.09 - (-0.04) / 0.01

= 0.3 ± √ 0.09 + 0.04 / 0.01

= 0.3 ± √ 0.13 / 0.01

= 0.3/0.01 ± √0.13/0.01

= 30 ± 0.36/0.01

x = 30 ± 36

x = 30 + 36 or 30 - 36

x = 66 or -6

Number of coolers can not be negative

Therefore, number of coolers produced when the cost is $19

is 66 coolers

3 0
3 years ago
An education firm measures the high school dropout rate as the percentage of 16 to 24 year olds who are not enrolled in school a
posledela

Answer:

The value of the test statistic z = -0.6606

Step-by-step explanation:

From the question we are told that

      The high dropout rate is \mu  = 6.1%  = 0.061

      The  sample size is  n = 1000

       The  number of dropouts x = 56

       The probability of having a dropout in 1000 people  \= x  = \frac{56}{1000}  =  0.056

Now setting up Test Hypothesis

 Null  H_o :  p = 0.061

 Alternative  H_a : p < 0.061        

The Test statistics is mathematically represented as

                 z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }

substituting values

               z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }

               z = -0.6606

6 0
3 years ago
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