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Ilia_Sergeevich [38]
3 years ago
11

Whats the slope of (-6,10) and (0,-5)

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0
I need help with slope also
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PLEASE HELP ME OUT...
e-lub [12.9K]

Answer:

y=-3

Step-by-step explanation:

there is no slope so x will not be used in the equation it also crosses at -3

3 0
3 years ago
What is -10=k+6 please show work thank you
Tresset [83]

Answer:

k=-16

Step-by-step explanation:

-10=k+6

subtract 6 both both sides to isolate the variable

-16=k

Happy Holidays!!

7 0
3 years ago
Read 2 more answers
To graph the inequality x > -3, draw an open circle on -3 and shade to the left.
dedylja [7]
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
8 0
2 years ago
Best explained and correct answer gets brainliest.
topjm [15]
U = (-2,3)

V = (3,0)

midpoint of UV

= ( (3-2)/2 , (3+0)/2 )

= ( 1/2 , 3/2)

= ( 0.5 , 1.5)

X = (0.5 , 1.5) [from fig]

midpoint of UV = X

W= (-2,-3)

V =( 3.0)

Y = ( (-2+3)/2 , (-3+0)/2 )

= (0.5 , - 1.5)

Y = ( 0.5 , -1.5) [ from fig ]

Y is the midpoint of WV

by midpoint theorem ,

UW = 2( XY )
6 0
3 years ago
Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%
garri49 [273]

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

<h3>LHS</h3>

\boxed{\sf \dfrac{cosA}{sinA}=cotA}

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

\\ \sf\longmapsto 1-cot2A

\\ \sf\longmapsto 1-\dfrac{1}{tan2A}

\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}

\\ \sf\longmapsto tan2A

8 0
2 years ago
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