Answer:
We conclude that segment QR is the shortest.
Hence, option B is true.
Step-by-step explanation:
First, we need to determine the missing angle m∠R
Given the triangle Δ∠PQR
m∠P = 48°
m∠Q = 83°
m∠R = ?
We know the sum of angles of a triangle is 180°.
m∠P+m∠Q+m∠R = 180°
48°+83°+m∠R=180°
m∠R = 180° - 48° - 83°
m∠R = 49°
Thus, the value of m∠R = 49°
We know that the longest side in a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.
Here,
m∠P = 48° is the shortest angle.
As the side QR segment is opposite the smallest angle i.e. m∠P = 48°
Therefore, we conclude that segment QR is the shortest.
Hence, option B is true.
I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:
(0-1)^2=4p(16-20)
Solving for p, p=-1/16.
Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:
(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1
Here, we have two values of x
x=sqrt(5)+1 and
x=-sqrt(5)+1
thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).
Answer: 77.11110
Step-by-step explanation:
