Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of line HG
2 answers:
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Let's find , which is essentially what the problem is asking, what
corresponds to an output of 2.
Let's solve below:
- Setting up what we know
- Substituting in
for
(I'm not sure if this is the correct expression for
- Subtract 4 from both sides to make a step to isolate
(what we are trying to find)
- Divide both sides of the equation by 23 to isolate
Thus the input is .
Answer: The answer is 314.28 cm² (approx.).
Step-by-step explanation: Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.
We need to find the area 'A' of the circular cross-section of the pipe.
Given, diameter of the circular section is
So, the radius of the circular cross-section will be
Therefore, cross-sectional area of the pipe is
Thus, the answer is 314.28 cm² (approx.).