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2 years ago

Find the measure of each angle.

Mathematics

2 answers:

Anton [14]2 years ago

5 0

Answer:

Step-by-step explanation:

1. 51 degrees

2. 90 degrees

3. 17 degrees

4. 107 degrees

5. 121 degrees

6. 68 degrees

hodyreva [135]2 years ago

4 0

Answer:

EBF= 51, EBA = 90, DBE = 17, DBC = 107, ABF = 141, DBF = 68

Step-by-step explanation:

EBF, 90-39 EBA, 180-90 DBE, 90-73, DBC,17+90 ABF, 90+51, DBF, 17+51

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Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

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3 years ago

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galina1969 [7]

Do percent over 100 and then cross multiply and you should receive your answer.
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3 years ago

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dimaraw [331]

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7 0

3 years ago

Read 2 more answers

A store charges $32 to print 80 greeting cards and $0.33 for each additional greeting card.

otez555 [7]

G=greeting cards
Equation A- 32+.33(g)

Equation B- T= 32+.33(10)

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3 years ago

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Anton [14]

Step-by-step explanation:

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3 0

2 years ago