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Otrada [13]
3 years ago
12

Find the domain and range of the following function ƒ(x) = 5|x - 2| + 4

Mathematics
1 answer:
Inessa [10]3 years ago
6 0

Answer:

this is the answer fod this lroblsm

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A city has 3 new houses for every 9 old houses. If there are 15 new houses in the city, how many old houses are there?
Arisa [49]

Answer:

45 old houses

Step-by-step explanation:

new houses : old houses

3 : 9

15 : ?

(3 = 1st ratio and 9 = 2nd ratio)

To find the missing ratio, divide the first ratio from the new ratio:

15 / 3 = 5

Take the product and multiply that by the second ratio to find the missing ratio:

9 x 5 = 45

6 0
2 years ago
Read 2 more answers
Find the equation in terms of x of the line through the points (-4,-4) and (5,-5)
zhuklara [117]

Answer:

The answer to your question is:  y = -1/9 x - 40/9

Step-by-step explanation:

Data

A (-4 , -4)

B (5, -5)

Formula

m = (y2 - y1) / (x2 - x1)

y = mx + b

(y - y1) = m(x - x1=

Process

m = (-5 + 4) / (5 + 4)

m = -1 / 9

( y +4) = -1/9 (x + 4)

y + 4 = -1/9 x - 4/9

y = -1/9 x - 4/9 - 4

y = -1/9 x - 4/9 - 36/9

y = -1/9 x - 40/9

5 0
3 years ago
9 squared divided by 3 cubed. Give expression in symbols and evaluate it? What is a exponential mot action with positive exponen
S_A_V [24]
There are numerous ways you can do this, but take a look at the attachment to see how I did it. I hope it answers your question! :)

7 0
3 years ago
Which of the following factored forms given below represent the correct factorization of the trinomial x^2 + 10x + 16
valina [46]
It would be 2 since that would give you the trio mail if expanded
5 0
3 years ago
Read 2 more answers
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
3 years ago
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