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3 years ago

I need help pls ASAP

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

3 0

2radical 10 for simplifying radical 40

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One eighth of the class graduated with an A average, 1/2 got a B, and the rest of the class had a C average. In a class of 800,

pogonyaev

I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!

8 0

3 years ago

Read 2 more answers

2 more than 5 groups of 3

Anvisha [2.4K]

5*3+2 = 15+2 = 17
The asnwer is 17.

5 0

3 years ago

Suppose you have $12,000 to invest. If part is invested at 10% and the rest at 15%, how much should be invested at each rate to

Ivahew [28]

X=invested at 10%12000-x=invested at 15% .10x+ (.15)(12000-x)=1440 ;; 12% of the total amount is 12% of $12000. .10x + 1800-.15x=1440
-0.05x=-360x=7200 12000-x=4800 $7200 at 10%=$720$4800 at 15%=$720 That is $12000 earning $1440, and that is 12%

3 0

3 years ago

Help please this is making me lose braincells- Giving brainliest

liraira [26]

Answer:

d - cost
a - number of attendees

<u>If budget is $99, then the equation is:</u>

99 = a + 96
a = 99 - 96
a = 3

Maximum number of attendees is 3

8 0

3 years ago

walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p

laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

$Y(x) = (20+x)(60-2x)$

Differentiating with respect to t ( time ),

$Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x$

Again differentiating with respect to t,

$Y''(x) = -4$

For maxima or minima,

$Y'(x) = 0$

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0

3 years ago