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galben [10]
2 years ago
8

Franco bought 2 cans of paint and 1/2 of a pint of special paint additive formulated to reduce

Mathematics
1 answer:
satela [25.4K]2 years ago
4 0

Answer:

1/4 a pint in each can

Step-by-step explanation:

honestly this is prob wrong anyways

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Find the mean of the picture below?
Kobotan [32]
The believe mean is four
8 0
3 years ago
Your petty cash has a balance of $73.28. Your Center Manager provides you with two receipts totalling $52.29. How much cash rema
Dvinal [7]

Answer:

Cash remaining in the petty cash box = 20.99 dollars

Explanation:

Given that,

Petty cash has a balance of = 73.28 dollars

Total receipt = 52.29 dollars

We need to find the remaining petty cash .

In order to find out the remaining cash, we will subtract total receipt from Petty cash balance.

Cash remain = Petty cash balance - total receipt

Cash remain = $73.28 - $52.29

Cash remain = 20.99 dollars

That's the final answer.

I hope it will help you.

4 0
3 years ago
Suppose the cost of college tuition is expected to increase 5% every year. How much will the tuition at a comunity college cost
evablogger [386]

Answer:

$7,596.43

Step-by-step explanation:

The cost of the college tuition is increasing 5% compounded annually for 5 years.

∴ A = P(1 + r%)ⁿ

where A = tuition fee after 5 years.

           P = current tuition

           r = rate of increase

            n = period

A =  $5,952(1 + 5%)⁵

     = $5,952(1 + 0.05)⁵

     =  $5,952 × 1.05⁵

     = $7,596.43

    =

8 0
3 years ago
Read 2 more answers
Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

7 0
3 years ago
If the test is worth 50 and you score 84% how many questions did you get wrong? Write the proportion?
quester [9]
You got 8 questions wrong.

10% of 50 is 5.
 x8               x8
________________
80% of 50 is 40.
84% of 50 is 42.


50-42= 8 questions wrong.




8 0
3 years ago
Read 2 more answers
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