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3 years ago

Ravi makes lemonade by mixing lemon juice and water.

Mathematics

2 answers:

Pepsi [2]3 years ago

5 0

Ingredients required to make 10 cups of lemonade = 10 cups lemon juice , 40 cups water

1 cup of lemon juice & 4 cups of water makes one glass of lemonade

So, lemon juice : water proportion, per unit lemon juice = 1 : 4

Hence, 10 cups of lemonade would be made by = 10 cups of lemon juice & 10 x 4 ie 40 cups of water.

For more related information, refer brainly.com/question/7810782?referrer=searchResults

Thepotemich [5.8K]3 years ago

3 0

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If the sum of the measures of the interior angles of a polygon is 1920°, how many sides does it have? math

Inessa05 [86]

Answer: There is no polygon with the sum of the measures of the interior angles of a polygon is 1920°.

Step-by-step explanation:

The sum of the measures of interior angles of a polygon with $n$ sides is given by:-

$(n-2)\times180^{\circ}$

Given: The sum of the measures of the interior angles of a polygon is 1920°.

i.e. $(n-2)\times180^{\circ}=1920^{\circ}$

$n-2=\dfrac{1920}{180}\\\\ n= \dfrac{1920}{180}+2\\\\ n=\dfrac{2280}{180}=12.67$

But number of sides cannot be in decimal.

Hence, there is no polygon with the sum of the measures of the interior angles of a polygon is 1920°.

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2 years ago

I got 8 green crayons for the a part just confused for the b part

Shalnov [3]

Answer:

Just apply the same method to part B

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2 years ago

Read 2 more answers

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

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3 years ago

The limit of tan4x/6x as x approaches 0

AleksandrR [38]

$\displaystyle\lim_{x\to0}\frac{\tan4x}{6x}=\lim_{x\to0}\frac{\sin4x}{4x}\times\frac{4x}{6x\cos4x}=\dfrac23\lim_{x\to0}\sec4x=\dfrac23$

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2 years ago

Subtract the sum of(8m-7n+6p)and(-3m-4-p)from the sum of (2m+4-3p)and(-m-n-p)

irinina [24]

8m,3n,9p would im guessing make the numbers to the rest of the problem

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