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Rzqust [24]
2 years ago
12

Help i'll give brainlist :0

Mathematics
1 answer:
liberstina [14]2 years ago
3 0

The rate of growth in the tree is 4 feet per year.

Height of tree at year 0 = 2 feet

Height of tree at year 1 = 6 feets

Height of tree at year 0 = 10 feets

Therefore, the difference in the heights of the tree from the previous year will be:

= 6 feet - 2 feet.

= 4 feet

In conclusion, the correct option is B.

Read related link on:

brainly.com/question/24730392

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What is the second partial product of 564x307
irinina [24]
564
307
1129 is your answer
3 0
3 years ago
Evaluate triple integral ∫ ∫ ∫ 8xydV, where E lies under the plane z = 1+x+y and above the E region in the xy-plane bounded by t
vazorg [7]

Answer:

\mathbf{=\dfrac{163.384}{15}}

Step-by-step explanation:

\int \int \limits_{E} \int \ 8 xy dV = \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} \int\limits^{1+x+y}_{0} \ 8xy dz dydx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} [ 8xyz]^{z=1+x+y}_{z=0}  \   \ dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy (1+x+y) dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy+8x^2y+8xy^2 \ \ dy dx

= \int\limits^{1}_{0}  \ [ 4xy^2+4x^2y^2+2.7xy^3]^{ y= \sqrt{x}}_{y-0} \ \  dx

= \int\limits^{1}_{0} \   4x (\sqrt{x})^2+4x^2(\sqrt{x})^2+2.7x(\sqrt{x})^3\ \  dx

= \int\limits^{1}_{0} \   4x^2+4x^3+2.7x^{5/2} \  dx

\mathbf{=\dfrac{163.384}{15}}

7 0
3 years ago
In 2012, researchers working with a very large population of health records found that 9.3% of all Americans had diabetes (sourc
icang [17]

Answer:

False. These events are dependent.

Step-by-step explanation:

A represent the event "the first individual has diabetes."

B represent the event "the second individual has diabetes."

The probability that the second individual has diabetes changes according to the probability that the first individual has diabetes.  Therefore these events are dependent.

3 0
3 years ago
What should I do ???
a_sh-v [17]
To find the area, you would multiply length times width.
For example, to find the area of problem number 1, I would multiply 8 (length) times 2 (width) to get the area of 16.
I hope this helped! If you need another example, feel free to ask!
:-)
3 0
2 years ago
Read 2 more answers
What expression is equivalent to -7(y-2)
morpeh [17]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

  • \sf - 7(y - 2)

  • \sf - (7 \cdot y) -(7 \cdot 2)

  • \sf - 7 y-( - 14)

  • \sf - 7 y + 14

The equivalent expression will be ~

\boxed{ \sf  - 7y + 14 \:  \: }

5 0
2 years ago
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