Answer:
f(t) = 1.22·(173/122)^(t/5)
Step-by-step explanation:
(a) An exponential growth (or decay) function can be written using the form ...
f(t) = (initial value)·(ratio in period)^(t/period)
Here, we're given an initial value of 1.22, a growth ratio of 1.73/1.22 in a period of 5 years, so we can write the function as ...
f(t) = 1.22·(173/122)^(t/5)
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(b) In 2038-2012 = 26 years, the value of the function is ...
f(26) = 1.22·(173/122)^(26/5) ≈ 7.50 . . . . million
Wooooooo hoooooooo you goooooooo
Answer:
Step-by-step explanation:
Given that X the time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.
We have 68 rule as 2/3 of total would lie within 1 std deviation, and 95 rule as nearly 95% lie within 2 std deviations from the mean.
We have std deviation = 10
Hence 2 std deviations from the mean
= Mean ±2 std deviations
=
±20
= 
Below 50, 0.25 or 2.5% would complete the exam.

Let's solve ~




I hope you understood the procedure, please let me know if you have any doubts