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Inessa [10]
3 years ago
12

According to the scatterplot below, which statement is correct? A graph titled Courses Completed versus Remaining Credits Needed

to Graduate has courses completed on the x-axis and Credits need to graduate on the y-axis. Points plotted are (4, 110), (8, 76), (16, 63), (20, 53), (24, 33). The input, or dependent variable, is courses completed. The output, or dependent variable, is credits needed to graduate. The input, or independent variable, is credits needed to graduate. The output, or independent variable, is courses completed.
Mathematics
2 answers:
almond37 [142]3 years ago
7 0

Answer:

option b

Step-by-step explanation:I took the test on edgenuity 2020 and got it right so there u go hope i helped!

kondaur [170]3 years ago
6 0

Answer:

Option B.

Step-by-step explanation:

It is given that a graph titled Courses Completed versus Remaining Credits Needed to Graduate has courses completed on the x-axis and Credits need to graduate on the y-axis.

Points plotted are (4, 110), (8, 76), (16, 63), (20, 53), (24, 33).

Since, x-axis represents the courses completed, therefore the input, or independent variable is courses completed.

Since, y-axis represents the Credits need to graduate, therefore the output, or dependent variable is Credits need to graduate.

Therefore, the correct option is B.

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I’m unsure of what this is. help someone
JulsSmile [24]
<h2>Part 1)</h2>

Let's analyze each part of the function:

FROM x = 0 TO x = 5:

We can find the equation of this line by using The Slope-Intercept Form of the Equation of a Line, that states:

The \ graph \ of \ the \ equation: \\ \\ y=mx+b \\ \\ is \ a \ line \ whose \ slope \ is \ m \ and \ whose \ y-intercept \ is \ (0, b)

So the y-intercept here is (0,4) and m=\frac{4}{5}, therefore:

\boxed{y=\frac{4}{5}x+4}

FROM x = 0 TO x = 5:

From the previous line, we know that at x=5 the output is:

y=\frac{4}{5}x+4 \\ \\ y=\frac{4}{5}(5)+4 \\ \\ y=4+4=8

So the point P_{1}(5,8) lies on both lines.

For this new line, the slope is m=-\frac{3}{5}

So, with the Point-Slope Form of the Equation of a Line we can find the equation of this other line:

The \ equation \ of \ the \ line \ with \ slope \ m \\ passing \ through \ the \ point \ (x_{1},y_{1}) \ is:\\ \\ y-y_{1}=m(x-x_{1})

So:

y-8=-\frac{3}{5}(x-5) \\ \\ y=8-\frac{3}{5}x+3 \\ \\ \boxed{y=-\frac{3}{5}x+11}

The graph is shown below.

<h2>Part 2)</h2>

The graph of the linear function f(x)=ax+b is a line with slope m=a and y-intercept at (0,b). From the items, we can assure that the following equations are linear functions:

\bullet 3y=2x-1.5 \ because \ y=\frac{2}{3}x-\frac{1}{2} \\ \\ \\ \bullet y=1 \ because \ y=m(0)+1 \\ \\ \\ \bullet 5(x+y)=-25 \ because \ 5x+5y=-25 \ \therefore 5y=-5x-25 \therefore y=-x-5

In conclusion, the other functions are nonlinear and they are:

\bullet \ y=x^2+3 \\ \\ \bullet \ y=x^3 \\ \\ \bullet \ y=12-x^2

7 0
3 years ago
The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of
Irina18 [472]

Answer:

The volume of the composite figure is 84π ≅ 263.89 inches³

Step-by-step explanation

- The composite figure consists of :

# Half sphere with radius 3 inches

# Cylinder with radius 3 inches and height 6 inches

# Cone with radius 3 inches and height 4 inches

- The volume of the sphere is 4/3 π r³

∴ The volume of the half sphere = 1/2 × 4/3 π r³ = 2/3 π r³

- The volume of the cylinder is π r² h

- The volume of the cone is 1/3 π r² h

* Now lets solve the problem

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∵ The volume of it = 2/3 π r³

∴ The volume = 2/3 × π × (3)³ = 18π inches³

- The volume of the cylinder

∵ The radius of the cylinder = 3 inches

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∴ Its volume = π × (3)² × 6 = 54π inches³

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∵ The radius of the cone = 3 inches

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∵ The volume of it = 1/3 π r² h

∴ Its volume = 1/3 π × (3)² × 4 = 12π inches³

- Add all the volumes to find the volume of the composite figure

∴ The volume = 18π + 54π + 12π = 84π = 263.89 inches³

* The volume of the composite figure is 84π ≅ 263.89 inches³

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