Answer:
Step-by-step explanation:
(x²-6x-3)(7x²-4x+7)= ?
Multiply each term of 2nd bracket with the 1st bracket:
=7x²(x²-6x-3) -4x(x²-6x-3) +7(x²-6x-3)
=7x^4-42x^3-21x^2-4x^3+24x^2+12x+7x^2-42x-21
Now solve the like terms:
=7x^4-46x^3+10x^2-30x-21
Therefore the answer is (x²-6x-3)(7x²-4x+7)=7x^4-46x^3+10x^2-30x-21 ....
I think it is the fourth one
The height of the can for this case is given by:
h = 40 mm
The radius of the can is given by:
r = (1 3/8) * h
Substituting values:
r = (1 3/8) * 40
r = 55 mm
Therefore, the diameter of the can is:
d = 2 * r
d = 2 * 55
d = 110 mm
Answer:
The diameter of the can will be:
d = 110 mm
Given:
The fees for a day student are $600 a term.
The fees for a boarding student are $1200 a term.
The school needs at least $720000 a term.
To show:
That the given information can be written as 
.
Solution:
Let x be the number of day students and y be the number of boarding students.
The fees for a day student are 
a term.
So, the fees for 
day students are 
a term.
The fees for a boarding student are 
a term.
The fees for 
boarding student are 
a term.
Total fees for day students and boarding student is:
The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.
Divide both sides by 600.
Hence proved.
