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xxTIMURxx [149]
2 years ago
5

What are the solutions of the quadratic equation? 4x^2+34x+60=0

Mathematics
1 answer:
insens350 [35]2 years ago
6 0

Answer:

Option 3) -6,-5/2

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^{2} +34x+60=0  

so

a=4\\b=34\\c=60

substitute in the formula

x=\frac{-34(+/-)\sqrt{34^{2}-4(4)(60)}} {2(4)}

x=\frac{-34(+/-)\sqrt{196}} {8}

x=\frac{-34(+/-)14} {8}

x_1=\frac{-34(+)14} {8}=-\frac{20}{8}=-\frac{5}{2}

x_2=\frac{-34(-)14} {8}=-6

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There is not sufficient evidence to support the claim.

Step-by-step explanation:

The claim to be tested is:

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<em>Hₐ</em>: The mean respiration rate of students is less than 32, i.e. <em>μ</em> < 32.

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7 0
2 years ago
The ratio of Michael and Neil’s ages is 7:6. If Neil is really 42 years old, how old is Michael?
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3 years ago
Let a and b be real numbers satisfying a^3 - 3ab^2 = 47 and b^3 - 3a^2 b = 52. Find a^2 + b^2.
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Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

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From 1, a(a² - 3b²) = 47...3

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