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Sati [7]
3 years ago
10

Name the property. a + b is a real number.*

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

a + b = b + a   \: \forall \: a,  \: b  \in \:   \R \ \\ a \times b = b \times a\: \forall \: a,  \: b  \in \:   \R \\ (a + b) + c = (b + c) + a\: \forall \: a,  \: b,  \: c,  \in \R \\ (a \times b) \times c = (b \times c) \times a \: \forall \: a,  \: b,  \: c,  \in \R \\a+0=0+a=0 \: \forall \: a,\in \:   \R \\a +b=c\: \forall \: a,  \: b,  \: c,  \in \R

Sati [7]3 years ago
4 0

Answer:

Closure Property of Addition

Step-by-step explanation:

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The first four stripes on a wall with 100 stripes are red , blue, white, and purple, These four colors repeat in the same order.
liubo4ka [24]

Answer: the 55th stripe is white

Step-by-step explanation:

The first four stripes on a wall with 100 stripes are red , blue, white, and purple. The four colors repeat in the same order. This means that Red always follow blue which is followed by white and then purple. This means that red would always start each new and consecutive set of four stripes and purple will always end it

We want to determine the 55th stripe. The last four stripes that include 55 ends with the 56th stripe. This means that the 56th stripe is purple. Therefore, the 55th stripe would be white because it follows purple.

3 0
3 years ago
What is a counterexample for the statement the difference between two integers is always positive
Maru [420]

We have to give counter example for the given statement:

"The difference between two integers is always positive"

This statement is not true. As integers is the set of numbers which includes positive and as well as negative numbers including zero.

Consider any two integers say '2' and '-8'. Now, let us consider the difference between these two integers.

So, 2 - 8

= -6 which is not positive.

Therefore, it is not necessary that the difference of two integers is only positive. The difference of two integers can be positive, negative or zero.

3 0
3 years ago
36= 2² x 3² how do i get the number to my prime factor
mojhsa [17]

Answer:

add up the exponents on each prime number

Step-by-step explanation:

2^2= 2x2

3^2=3x3

so 36=2^2x3^2=2x2x3x3

5 0
3 years ago
Read 2 more answers
Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
4 years ago
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