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3 years ago

Solve for x x -8 = -14

Mathematics

2 answers:

Semenov [28]3 years ago

7 0

Answer:

6/93/(63)

Step-by-step explanation:

yan sagot sa maht problem?

Anit [1.1K]3 years ago

4 0

Answer:

-6

Step-by-step explanation:

x - 8 = -14

Add 8 to both sides of the equation

x - 8 + 8 = -14 + 8

x = -6

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What is 21 1/2‐6 1/2

snow_tiger [21]

Answer

Step-by-step explanation:

Please mark brainliest.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%20%7Btan%7D%5E%7B3%7D%20x%20%5C%3A%20dx" id="TexFormula1" title=" \int {tan}^{3} x \

r-ruslan [8.4K]

Answer:

$\frac{ {tan}^{2} x}{2} + \ln( |cos \: x| ) + C$

Step-by-step explanation:

$\int {tan}^{3} x \: dx$

$\int \: tan \: x \times {tan}^{2} x \: dx$

$\int \: tan \: x( {sec}^{2} x - 1) \: dx$

distribute

$\int \: tan \: x \: {sec}^{2} x - tan \: x \: dx$

$\int \: tan \: x \: {sec}^{2} x \: dx \: - \int \: tan \: x \: dx$

$\int \: tan \: x \: {sec}^{2} x \: dx \: - \int \frac{sin \: x}{cos \: x} \: dx$

First integrand

let tan x = u

du = sec²x dx

Second integrand

let cos x = z

dz = -sin x dx

$= \int u \: du \: - \int - \frac{1}{z} dz$

$= \frac{ {u}^{2} }{2} + \ln( |z| ) + C$

$= \color{red}{ \boxed{ \frac{ {tan}^{2} x}{2} + \ln( |cos \: x| ) + C}}$

7 0

3 years ago

Whats the value of n? <img src="https://tex.z-dn.net/?f=40%20%3D%20-%5Cfrac%7B5n%7D%7B8%7D" id="TexFormula1" title="40 = -\frac{

adell [148]

Isolate the n. First, multiply 8 to both sides

40(8) = (-5n/8)(8)

40(8) = -5n

Multiply.

320 = -5n

Isolate the n. Note the equal sign. What you do to one side, you do to the other. Divide -5 from both sides

(320)/-5 = (-5n)/-5

n = 320/-5

n = -64

-64 is your answer for n

hope this helps

7 0

4 years ago

Find an equation of the circle that satisfies the given conditions. (Use the variables x and y.)

prohojiy [21]

Answer:

$x^2 + y^2 = 52$

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Equation of a circle:

The equation of a circle with center $(x_0,y_0)$ and radius r has the following format:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Center at the origin;

This means that $x_0 = 0, y_0 = 0$

$(x - x_0)^2 + (y - y_0)^2 = r^2$

$(x - 0)^2 + (y - 0)^2 = r^2$

$x^2 + y^2 = r^2$

Passes through (4, 6)

The radius is the distance from this point to the center. So

$r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r = \sqrt{(4-0)^2+(6-0)^2}$

$r = \sqrt{16+36}$

$r = \sqrt{52}$

$r^2 = 52$

Then

$x^2 + y^2 = r^2$

$x^2 + y^2 = 52$

8 0

3 years ago

What is the answer to this expression 9-(3-6x)

Fudgin [204]

Simplified would be 6+6x

6 0

3 years ago

Read 2 more answers