Answer:
first piece = 5 m
second piece = 2(5) + 2 = 12 m
third piece = 3(2x + 2) = 6(5) + 6 = 36 m
Step-by-step explanation:
The question is incomplete, the length of the actual rope is unknown but it should be given . Let us assume the length of the rope is 53 meters.
The rope is cut into 3 pieces of different length.
first piece = x
second piece = 2x + 2
third piece = 3(2x + 2) = 6x + 6
Since the length of the actual rope is assumed to be 53 meters .The length of the first piece, second piece and third piece can be calculated as follows.
we add the length of the pieces to get the actual length of each piece. Therefore,
x + 2x + 2 + 6x + 6 = 53
collect like terms
9x + 8 = 53
9x = 53 - 8
9x = 45
x = 45/9
x = 5 meters
first piece = 5 m
second piece = 2(5) + 2 = 12 m
third piece = 3(2x + 2) = 6(5) + 6 = 36 m
12)
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13)
Answer: -4x^3 y^10
-2x^3 • 2 = 4 (because 2•2 is 4, they don’t share the same variable so you just multiply the base)
y^9 • y^1 (9+1=10)
-4x^3 y^10
their relative speed is 4 mph. so we put
4 mph = (25 mi)/x => x=25/4.
FIRST YOU FIND THE TOTAL NUMBER OF RIGHT-HANDED BY DOING
5:8 = 45:x
CROSS MULTIPLY : 5x = 45(8)
5x = 360
x = 360/5
x = 72
THE TOTAL NUMBER OF BATTERS = 45 + 72 =117
THE RATIO OF LEFT-HANDED BATTERS TO THE TOTAL NUMBER OF BATTERS IS 45/117 ( YOU CAN SIMPLIFY BOTH BY 9 ); 45/117 = 5/13.
HOPE THIS HELPED