Answer: $4,375
Explanation:
Annual Depreciation at end of year 5 is the same as every year as this is classical straight line depreciation.
= (Cost - Salvage value) / Useful life
= (40,000 - 5,000) / 8
= $4,375
Answer:
c. $155,320
Explanation:
The computation of the project cost is shown below:
= Cash inflow in year 1 × discount factor in year 1 + cash inflow in year 2 × discount factor in year 2
= $80,000 × 0.909 + $100,000 × 0.826
= $72,720 + $82,600
= $155,320
By multiplying the discount factor of each year with the cash inflow of that year, the present value of that year will come.
Answer:
a) $3
b) $2
c) 1449
Explanation:
Given:
The cost for a carton of milk = $3
Selling price for a carton of milk = $5
Salvage value = $0 [since When the milk expires, it is thrown out ]3
Mean of historical monthly demand = 1,500
Standard deviation = 200
Now,
a) cost of overstocking = Cost for a carton of milk - Salvage value
= $3 - $0
= $3
cost of under-stocking = Selling price - cost for a carton of milk
= $5 - $3
= $2
b) critical ratio =
or
critical ratio =
or
critical ratio = 0.4
c) optimal quantity of milk cartons = Mean + ( z × standard deviation )
here, z is the z-score for the critical ration of 0.4
we know
z-score(0.4) = -0.253
thus,
optimal quantity of milk cartons = 1,500 + ( -0.253 × 200 )
= 1500 - 50.6
= 1449.4 ≈ 1449 units