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Molodets [167]
3 years ago
8

Anne Katz, owner of Katz Sport Shop, loans $8,000 to Shelley Slater to help her open an art shop. Shelley plans to repay Anne at

the end of 8 years with interest compounded semiannually at 8 percent. At the end of 8 years, Anne will receive:
Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0
A= P(1 + r/n) ^nt
=8000(1+0.08/2)^8x2
=8000(1.04)^16
=$14983.85
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What is the 100th term of this sequence:<br><br> an=2n-5
ohaa [14]
A(100) = 2(100) - 5 = 195

This means 195 is the 100th term. Hope this helps!!
6 0
3 years ago
Read 2 more answers
(-7) + b = (-11) PLEASE HELP
Alex
B=-4 because the7 turns positive then you add -11+7 which is -4
6 0
3 years ago
2a + b = 3 and a - 3b = 5
vfiekz [6]

Answer:

a= 2 b=-1

Step-by-step explanation:

a-3b=5

or, a= 5+3b_(i)

substituting value of a in 2a+b=3,

2×(5+3b)+b=3

or, 10+6b+b=3

or, 7b=3-10

or, 7b=-7

b= -1

substituting value of b in(i),

a=5+3b

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6 0
3 years ago
A TV company when purchasing thousands electronic components apply this sampling plan: randomly select 15 of them and then accep
katrin [286]
<h2>Answer with explanation:</h2>

According to the Binomial probability distribution ,

Let x be the binomial variable .

Then the probability of getting success in x trials , is given by :

P(X=x)=^nC_xp^x(1-p)^{n-x} , where n is the total number of trials or the sample size and p is the probability of getting success in each trial.

As per given , we have

n = 15

Let x be the number of defective components.

Probability of getting defective components = P = 0.03

The whole batch can be accepted if there are at most two defective components. .

The probability that the whole lot is accepted :

P(X\leq 2)=P(x=0)+P(x=1)+P(x=2)\\\\=^{15}C_0(0.03)^0(0.97)^{15}+^{15}C_1(0.03)^1(0.97)^{14}+^{15}C_2(0.03)^2(0.97)^{13}\\\\=(0.97)^{15}+(15)(0.03)^1(0.97)^{14}+\dfrac{15!}{2!13!}(0.03)^2(0.97)^{13}\\\\\approx0.63325+0.29378+0.06360=0.99063

∴The probability that the whole lot is accepted = 0.99063

For sample size n= 2500

Expected value : \mu=np= (2500)(0.03)=75

The expected value = 75

Standard deviation :  \sigma=\sqrt{np(1-p)}=\sqrt{2500(0.03)(0.97)}\approx8.53

The standard deviation = 8.53

6 0
3 years ago
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Varvara68 [4.7K]
32, that’s just 2 to the fifth power so 2*2*2*2*2
3 0
3 years ago
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