Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
Add them all, which is -216. Divide by the number of values, which is the mean of -36.
One square grid has an area of 400.
Another square grid has an area of 256.
The area of the third grid can be:
(squares in third grid) + 256 = 400
OR
256 + 400 = (squares in third grid)
We get this by applying the Pythagorean theorem.
So, the squares in the third grid can either be 144 or 656. And we only have 144 as an option, so that is your answer.
Your final answer is D. 144.
Answer:
1) £2 = €2.32
£5 = €5.80
£50 = €58
2) The graph will be a straight line
3) (0, 0)
4) Label the independent variable, £ on the x-axis and dependent variable € on the y-axis
Step-by-step explanation:
1) The given conversion factors is £1 = €1.16
Therefore;
£2 = 2 × €1.16 = €2.32
£2 = €2.32
£5 = 5 × €1.16 = €5.80
£5 = €5.80
£50 = 50 × €1.16 = €58
£50 = €58
2) The shape of the plot of the directly proportional currencies graph will be a straight line
3) Given that the £ is directly proportional to the € and that the value of the € can be found directly by multiplying the amount in £ by 1.16, without the addition of a constant, the graph crosses the axes at the origin (0, 0)
4) The y-axes which is the dependent variable should be labelled €, while the x-axis which is the independent variable should be labelled £
<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION:
</u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y = 
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.
