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m_a_m_a [10]
3 years ago
15

After 10 months the simple interest earned annually on an investment of $6000 was $769. Find the interest rate to the nearest te

nth of a percent.
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0
Simple interest = $769
Principal = $6000
Rate = ?
Time = 10 months (must convert to years if in months) = 10/12 = 0.833
Formula
I = prt
Substitute
769 = 6000 × r × 0.833
769 = 4998r
Divide both sides by 4998
769/4998 = 4998r/4998
0.15386 = r
(to the nearest tenth of a percent) = 0.15
Therefore, your rate is 0.15%.
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________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

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<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

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