Can someone write a full proof for #20?
1 answer:
You might be interested in
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W =
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
Pool A.
Step-by-step explanation:
This can be solved through ratios. You would write it as So,
for the first one, and
for the second. You might want to use a calculator for that part, but you could also change the gallons to cups, which gives you a much better number of 10.515. So,
, and
So, pool A is at a faster rate. If you want it in gallons per minute, it's by 0.01 (with the 1 repeating) gallons per minute. By cups, it's 0.17525 cups per minute.
(The reason I did not do this by cross multiplying and dividing ratios is because it gives you the exact same answer if you are finding it per one, as I am here with per one minute. You can do it this way, it just wastes a bit of time.)