<h3>
Answer: -3x-3y=-30= x=−y+10 </h3><h3>x+y+10= x=−y+10</h3>
Step-by-step explanation:
We have that point A is at 3.
This is 3 units to the right of 0 on the number line.
The point that is opposite of A should be 3 units to the left of 0.
That point will be at -3.
Therefore you have to choose the point that is on -3.
It should be similar to one in the attachment.
Answer:
1/8
Step-by-step explanation:
In this equation, you are solving for y. Simply isolate the variable by adding 1/4 to each side. The -1/4 and 1/4 will cancel out on the right side of the equation, leaving only y:
5/4 = y - 1/4
5/4 + 1/4 = y - 1/4 + 1/4
6/4 = y
y = 6/4
Don't forget to simplify y:
y = 3/2
Answer:
18" X 18" X 36"
Step-by-step explanation:
Given a square base container of height h, let a side of the base =s
The volume of the container,
If the sum of its height and girth (the perimeter of its base) equals 108 in

Substituting h=108-4s into V

We are required to determine the maximum volume of such container, first we take the derivative:

Optimizing:

Recall that: h = 108-4s

The dimensions of the carton are 18" X 18" X 36".